I am stuck on this problem and appreciate any help. Thanks
The speed of a moving bullet can be determined by allowing the bullet to pass through two rotating paper disks mounted a distance d apart on the same axle From the angular displacement Δθ of the two bullet holes in the disks and the rotational speed of the disks, we can determine the speed v of the bullet. Find the bullet speed for the following data: d = 90 cm, ω = 950 rev/min, and Δθ = 31.0°.
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Answer in m/s
The paper disks rotated 31 degrees in the time between when the bullet went through the first disk to when it went through the second disk.
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The disks were rotating at 950 revolutions per minute, convert this to degrees per second
950 rev/min x 360 deg/rev / 60 seconds/min = 5700 deg/sec
if something traveled 31 degrees at a rate of 5700 deg/sec, then it took
31/5700 = 0.00544 seconds between when the bullet hit the first disk to when it hit the second disk
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The bullet traveled 90cm which is 0.9 meters in 0.00544 seconds
0.9/0.00544 = 165.5 m/s
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Help needed to find the speed?